Converging and diverging lenses in a lab
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- Converging and diverging lenses in a lab
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Converging and diverging lenses in a lab
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[post_date] => 2025-01-09 21:27:00
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[post_content] => Practice Passage (Question 1-5)
*This passage is the property of Khan Academy and has been reformatted into an AAMC-style interface in their entirety by MedLife Mastery. MedLife Mastery does not endorse and is not an affiliate of Khan Academy.
A student is conducting a lab experiment to determine the properties of a multiple lens system. She hopes that she will be able to develop an apparatus for a new microscope eyepiece. The lenses are fixed in place on an optical bench as seen in the diagram (Figure 1). A diverging lens is fixed at point C, and a converging lens is fixed at point E. With this set up, points B and D represent the focal points of the diverging lens, and points C and G represent the focal points of the converging lens. The distance between adjacent lettered points on this optical bench is 10cm.
Figure 1. The lab setup by the student, including the converging and diverging lens.
With this arrangement, the student places an object at different points on the optical bench and stands to the right of the arrangement past point I. Once the object is in place, the student looks through the lenses and observes the image created by the multiple lens system.
[post_title] => Converging and diverging lenses in a lab
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[question] => If the student were to place an object at point B, where would the image be seen by the student?
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[answer] => 1
[description] => Reason for the Correct Answer:
The diverging lens will always create virtual images located between the lens and the focal point.
Converging lenses will create images with positive image distance if the object is located outside the focal point, and negative image distances if the object is located inside the focal poin
The image created by the diverging lens will be somewhere between B and C, and since this is located outside the focal point of the converging lens
Since the image created by the diverging lens is outside the focal length of the converging lens the image distance created by the converging lens will positive and so to the right of point E
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[answers] => Array
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[0] => Array
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[each_answer] => A. To the right of point E
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[1] => Array
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[each_answer] => B. Between C and E
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[2] => Array
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[each_answer] => C. Between B and C
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[3] => Array
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[each_answer] => D. To the left of point B
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[1] => Array
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[quiz_unique_key] => 3873426850
[question] => The student places a 4cm tall object right side up at point A, and the final image produced by the two lens system was an upside down image which was 4cm tall. What would be the total magnification of the two lens system in this example?
[value] => Array
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[answer] => 3
[description] => Reason for the Correct Answer:
The magnification gives the number you multiply the height of the object by to find the image height and orientation
The orientation of the image is inverted so the magnification must be negative
Since the size of the object is the same, but the image is inverted, the total magnification would be -1
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[answers] => Array
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[0] => Array
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[each_answer] => A. +1
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[each_answer] => B. +4
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[each_answer] => C. -1
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[each_answer] => D. -4
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[2] => Array
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[quiz_unique_key] => 83407773
[question] => If the student placed an object at point D, what kind of image would be created and where would it be created?
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[answer] => 1
[description] => Reason for the Correct Answer:
Since the object is placed in front of the diverging lens, it has no effect on the image.
The object is placed within the focal length of the converging lens.
Since the object is placed inside the focal length of the converging lens, the image will be virtual and to the left of point D.
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[answers] => Array
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[0] => Array
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[each_answer] => A. A virtual image to the left of point D
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[1] => Array
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[each_answer] => B. A real image to the left of point D
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[2] => Array
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[each_answer] => C. A virtual image to the right of point D
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[3] => Array
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[each_answer] => D. A real image to the right of point D
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[3] => Array
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[quiz_unique_key] => 2377279144
[question] => What is the lens strength of the diverging lens alone?
[value] => Array
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[answer] => 4
[description] => Reason for the Correct Answer:
Lens power is given by P=1/f.
The focal length of the diverging lens is 10cm.
Don’t forget to convert to meters.
P=1/f = 1/0.1m = 10 D.
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[answers] => Array
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[0] => Array
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[each_answer] => A. 0.1 Diopters
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[1] => Array
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[each_answer] => B. 0.5 Diopters
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[2] => Array
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[each_answer] => C. 5 Diopters
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[3] => Array
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[each_answer] => D. 10 Diopters
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[quiz_unique_key] => 2261298308
[question] => If an object placed at point A were slowly moved toward point C, what would happen to the image created by the two lens system?
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[answer] => 2
[description] => Reason for the Correct Answer:
The image created by the diverging lens will be seen to move towards point C, since diverging lenses always create images between the object and the lens.
Point C is the focal point of the converging lens.
Since the image created by the diverging lens moves toward the focal point of the converging lens, the image location will be seen to move to the right and increase in size.
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[answers] => Array
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[0] => Array
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[each_answer] => A. The image position would move to the right and the size of the image would get smaller
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[each_answer] => B. The image position would move to the right and the size of the image would get larger
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[2] => Array
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[each_answer] => C. The image position would move to the left and the size of the image would get larger
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[each_answer] => D. The image position would move to the left and the size of the image would get smaller
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